## Search found 46 matches

- Mon Sep 10, 2012 6:08 am UTC
- Forum: Mathematics
- Topic: Random(probably simple) Combinatorics problem
- Replies:
**2** - Views:
**1636**

### Re: Random(probably simple) Combinatorics problem

A nice little problem. My solution is in the spoiler; it's not obvious, but the final formula is simple enough. Let's look first at the 2x2 case. Consider the first list: "1, 2". Once you've placed these numbers in the final sequence (e.g. x1x2, or 1xx2) there's only on...

- Mon Aug 27, 2012 6:41 am UTC
- Forum: Mathematics
- Topic: collection of problems
- Replies:
**10** - Views:
**1828**

### Re: collection of problems

because, if x-(n-1) is divisible by n, then [x-(n-1)]+n = x+1 is divisible by n too. Exactly. You've got your answer, and you've got your proof that it's correct. But I would like to be able to express that more... formally. Be careful. There's a trap here. Laying out a proof formally should mean n...

- Sun Aug 26, 2012 5:15 pm UTC
- Forum: Mathematics
- Topic: collection of problems
- Replies:
**10** - Views:
**1828**

### Re: collection of problems

rolo91 wrote:The problem is that I don't know how to proof that this:(x-1) is divisible by 2

(x-2) is divisible by 3

(....)

(x-9) is divisible by 10

implies this:(x+1) divides 2,3,4,5,6,7,8,9 and 10

Earlier, you said that:

rolo91 wrote:I know (x+1) divides 2,3,4,5,6,7,8,9. and 10.

How do you know that?

- Sun Aug 26, 2012 12:47 pm UTC
- Forum: Mathematics
- Topic: collection of problems
- Replies:
**10** - Views:
**1828**

### Re: collection of problems

What can you say about (x+1)?

- Tue Aug 21, 2012 6:49 am UTC
- Forum: Mathematics
- Topic: Problems for Freshpeople
- Replies:
**9** - Views:
**2055**

### Re: Problems for Freshpeople

I'm not sure what a TA is TA - Teaching Assistant. The particulars of the position will vary from place to place; at the university I was at, the TA would be expected to mark certain assignments (ones that didn't count much towards the final mark), occasionally go through homework problems with the...

- Tue Aug 14, 2012 12:36 pm UTC
- Forum: Mathematics
- Topic: Weighting time spans by age, etc.
- Replies:
**6** - Views:
**1482**

### Re: Weighting time spans by age, etc.

Let me compare six months (0.5 years), starting from the 13th or 25th birthday, as a worked example: 0.5 years starting at the 13th birthday: y=13, z=0.5. Length of subjective time experienced: ln(13.5)-ln(13)=0.03774 0.5 years starting at the 25th birthday: y=25, z=0.5. Length of subjective time e...

- Tue Aug 14, 2012 11:48 am UTC
- Forum: Mathematics
- Topic: Weighting time spans by age, etc.
- Replies:
**6** - Views:
**1482**

### Re: Weighting time spans by age, etc.

That's pretty straight forward, but I think it's the other way around to what I was having in mind. Two hours at age thirteen don't feel like just over one twenty-five-year-old hour; the younger hours feel longer. If you multiply by b/a, you get three hours and fifty minutes of 25-year-old time out...

- Tue Aug 14, 2012 10:09 am UTC
- Forum: Mathematics
- Topic: Weighting time spans by age, etc.
- Replies:
**6** - Views:
**1482**

### Re: Weighting time spans by age, etc.

Let me take the experience of one second at age 1 as a baseline; call that an experienced time of 1 second. At age 2, that second appears half as long in comparison to my age, so that's an experienced time of 0.5. At age four, similarly, that's an experienced time of 0.25. At age x, that's an experi...

- Tue Aug 14, 2012 7:43 am UTC
- Forum: Mathematics
- Topic: Collatz conjecture
- Replies:
**11** - Views:
**2961**

### Re: Collatz conjecture

Choosing a multiple of three would be a good idea. Hmmm. A multiple of three cannot be part of a loop; 3x+1 can never lead to a multiple of 3, and x/2 can only lead to a multiple of 3 if starting from a multiple of three. Thus, no multiple of 3 can be reached from any smaller number at any point, n...

- Mon Aug 13, 2012 8:44 am UTC
- Forum: Mathematics
- Topic: Collatz conjecture
- Replies:
**11** - Views:
**2961**

### Re: Collatz conjecture

I've been thinking about this conjecture... and I think I may be partway to a proof, though under completely different lines to the original poster. First of all, I'll take a slightly modified version of the conjecture. If x is even, I divide by two; if x is odd, I multiply by three and add one. (Th...

- Fri Aug 03, 2012 7:39 am UTC
- Forum: Mathematics
- Topic: The Shortest String Containing all Permutations of n Symbols
- Replies:
**29** - Views:
**28117**

### Re: The Shortest String Containing all Permutations of n Sym

It's obvious that any two permutations which share the same n+1 digit will 'contract' to two distinct permutations like I want them to. I had been assuming that all the interesting cases were of this sort. However, I also think CCC is right, that the issue is when you have two permutations that sha...

- Thu Aug 02, 2012 2:55 pm UTC
- Forum: Mathematics
- Topic: The Shortest String Containing all Permutations of n Symbols
- Replies:
**29** - Views:
**28117**

### Re: The Shortest String Containing all Permutations of n Sym

If you remove all of the digits 'n+1', the string will then (as above) contain at least n+1 copies of each of the n! permutations of the digits 1,...,n. I think that's not quite right. Consider the sequence of digits 41234. This contains two unique length-four sequences (4123 and 1234), but removin...

- Mon Jul 30, 2012 7:52 am UTC
- Forum: Mathematics
- Topic: A Thread for scratch123's Random Math Questions
- Replies:
**71** - Views:
**16114**

### Re: Sum of digits and base n

I don't think Benford's Law applies here; it's applicable to random distributions with positive skew and a mean greater than the median. It's not applicable to a uniformly distributed random number, and the distribution of all integers should match that of a uniformly distributed random integer, sur...

- Sat Jul 28, 2012 7:05 pm UTC
- Forum: Mathematics
- Topic: A Thread for scratch123's Random Math Questions
- Replies:
**71** - Views:
**16114**

### Re: Sum of digits and base n

If, and only if, the sum of the digits of a positive integer n in base B adds up to a multiple of (B-1), then n is itself a multiple of (B-1). This can be applied recursively; you can find the sum of the digits of n, and then the sum of the digits of that, and so on, continuing until the result if o...

- Mon Jul 23, 2012 1:12 pm UTC
- Forum: Mathematics
- Topic: Largest 3 consecutive semi-primes?
- Replies:
**19** - Views:
**6029**

### Re: Largest 3 consecutive semi-primes?

So, are you sure those are the lowest 7-chains? If smaller 7-chains exist, then there is a bug in my program. It's not impossible. To put that lowest sequence in terms of prime factors: (7*11*2749; 2*3*35279; 5*5*8467; 2*2*52919; 3*37*1907; 2*109*971; 13*19*857) Also, can there be two 7-chains that...

- Mon Jul 23, 2012 9:06 am UTC
- Forum: Mathematics
- Topic: Largest 3 consecutive semi-primes?
- Replies:
**19** - Views:
**6029**

### Re: Largest 3 consecutive semi-primes?

7-chains exist. I threw together a piece of C code and did a quick brute-force search. The lowest sequence found was (211673; 211674; 211675; 211676; 211677; 211678; 211679) - the highest prime factor in that sequence was 52919. Sequences: (211673; 211674; 211675; 211676; 211677; 211678; 211679&...

- Sun Jul 22, 2012 10:29 am UTC
- Forum: Mathematics
- Topic: Largest 3 consecutive semi-primes?
- Replies:
**19** - Views:
**6029**

### Re: Largest 3 consecutive semi-primes?

Okay, so you've got six primes, p, q, r, s, t and u, where p*q+1=r*s and r*s+1=t*u. The lowest triple is <33, 34, 35>. Since 4 cannot be part of such a triple, no triple may include a multiple of 4. Therefore, p*q-1 and t*u+1 must both be multiples of 4. Therefore, r*s is even. Therefore, either r o...

- Tue Jul 17, 2012 7:09 am UTC
- Forum: Mathematics
- Topic: Proof preference
- Replies:
**6** - Views:
**2127**

### Re: Proof preference

I think I prefer it when the lemmas are presented first, one after the other. Then I can run from the top of the proof to the bottom, checking that every step follows from the previous step, until I get to the end; I don't have to go back and forth, nor do I have to remember which lemmas remain unpr...

- Sat Jul 14, 2012 7:37 am UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

All linear transformations on R 2 (the vector space of pairs of real numbers) are completely defined by where they take (1,0) and (0,1). It isn't hard to build the matrix once you know where they go -- the first column of the matrix is where it takes (1,0) and the second column where it takes (0,1)...

- Thu Jul 12, 2012 8:04 am UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

Just started learning about matrices. Question; what is the practical application of matrices? Why the seemlingly arbitrary multiplication rules? I want to understand the point behind what I'm doing rather than just learn to go through the motions. Let me demonstrate merely a single practical appli...

- Thu Jul 12, 2012 7:36 am UTC
- Forum: Mathematics
- Topic: How can I tell if Im good at "Real Math"? + Emphasis anxiety
- Replies:
**11** - Views:
**4785**

### Re: How can I tell if Im good at "Real Math"? + Emphasis anx

I think I'm decent at math, but I feel like about 90% of that is me faking it. There's a simple test that will tell you if you are, in fact, faking it or not. Are you getting the right answers, consistently? If yes, then you are not faking it. If no, then I'd argue that you are not 'decent at math'...

- Mon Jul 09, 2012 2:31 pm UTC
- Forum: Mathematics
- Topic: Seating around a Table
- Replies:
**12** - Views:
**3851**

### Re: Seating around a Table

In how many ways, order matters, can 14 married couples be seated in chairs consecutively 1 to 28 at a round table so that one man is always between two women and no man ever sits next to his wife? Do you mean so that each man is between two wonen, thus mwmwmwmw... or so that at least one man is be...

- Sun Jul 08, 2012 7:15 pm UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

New math question, is there a trick to factoring polynomials with prime numbers? In most cases I can get the answer just by looking at it, the general pattern seems to be something like (1st nx + or - 1)(x + or - last n), as in 3x^2 - 29x - 10 = (3x + 1)(x - 10). But of course they don't all do tha...

- Thu Jul 05, 2012 9:57 pm UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

Ccc, I've put your link in my reading list, thanks for the lesson. I'm really curious as to how light is measured at the same speed no matter what speed you're moving at. Hawking says it's because everyone experiences time differently, I'm still trying to work out that concept. His special on time ...

- Thu Jul 05, 2012 7:41 am UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

Linear simultaneous equations? You mean this? Because that seems pretty simple. In fact I'm glad you led me to look that up, I just learned something new. :P Yes, that's exactly what I mean. Now, I'm only going to go into Special Relativity; General Relativity is a whole different story (and uses s...

- Wed Jul 04, 2012 6:23 am UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

Thanks for the insight, there's so much I don't know that I want to understand. I thought math was the only real obstacle (I only ever considered math to be my dyslexia, everything else was learnable in theory) but it looks like I'll have to tackle a lot of difficult concepts in a broad spectrum. W...

- Mon Jul 02, 2012 8:19 am UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

Also: - 81(x^8)(y^6) / 39 (x^9)(y^4) = -27(y^2) /13x That looks like simplifying fractions, both numbers can be divided by 3 to get that result, did the others stay the same because they can't be simplified anymore? Is there a trick to this I'm not seeing? You have the problem exactly; it is simpli...

- Sun Jul 01, 2012 11:09 am UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

On the subject of negative and positive numbers and multiplication; this goes back to the definition of multiplication at repeated addition. a*b is simply (a+a+...+a) with b a's. So: 2*3=2+2+2 3*7=3+3+3+3+3+3+3 4*5=4+4+4+4+4 This leads immediately to a consequence; (a*b)+(a*c) = (a+a+...{b times}......

- Sat Jun 30, 2012 5:03 pm UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

I would like to add that you should really try and take a lot away from your first question and dopefish's response. I agree wholeheartedly with Birk. Dopefish's answers to your first and third question did not give rise to long discussions, because they do not lend themselves to extended discussio...

- Fri Jun 29, 2012 8:12 am UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

Also... Given the equation 5(-3x - 2) - (x - 3) = -4(4x + 5) + 13 I thought the answer stops at -16x - 7, but the detailed solution continues. Add 16x + 7 to both sides and write the equation as follows 0 = 0 Why do that? @.@ Why not? It's a valid step, and you can take any valid step you like at a...

- Fri Jun 29, 2012 6:42 am UTC
- Forum: Mathematics
- Topic: Linear-time arithmetic prime test yields factors
- Replies:
**13** - Views:
**4515**

### Re: Linear-time arithmetic prime test yields factors

BlueNight wrote:What I'd need for a real test is an optimized big-int library.

You might find libgmp useful, then. Just watch the initialisation and clearing of the variables.

- Wed Jun 27, 2012 9:41 am UTC
- Forum: Mathematics
- Topic: The Most Important Math
- Replies:
**48** - Views:
**19397**

### Re: The Most Important Math

I think that The Secret Number is relevant at this point. -------------- What is the most important branch of mathematics? That depends. Important is defined as "Having relevant and crucial value". In order for it to be most important, therefore, it has to be both highly relevant and highl...

- Mon Jun 25, 2012 7:55 am UTC
- Forum: Mathematics
- Topic: Want to study astronomy... bad at math
- Replies:
**117** - Views:
**30813**

### Re: Want to study astronomy... bad at math

Math is a skill. It can be learnt, and yes, it can be learnt at any age. What you need for best results are a good teacher, a clear willingness to learn, and a lot of practice. With a bit of effort, a lot of luck, and the right study materials, it may be possible to manage without the good teacher, ...

- Sat Jun 23, 2012 9:23 pm UTC
- Forum: Mathematics
- Topic: Polynomials with integer coefficients
- Replies:
**1** - Views:
**841**

### Polynomials with integer coefficients

For a polynomial a 1 x n +a 2 x n-1 +a 3 x n-2 +---+a n-1 x+a n =0, where the coefficients a 1 , a 2 , a 3 , --- a n-1 ,a n are all integers and a 1 is nonzero, all rational solutions for x will have denominators that are factors of a 1 when written in the simplest form. This holds for all polynomia...

- Fri Jun 22, 2012 4:01 pm UTC
- Forum: Mathematics
- Topic: Making the most out of a djinn's offer
- Replies:
**14** - Views:
**3243**

### Re: Making the most out of a djinn's offer

Ask for one dollar for every digit in the decimal expansion of pi. Of course, that's assuming you want an infinite amount of money and won't be crushed by the weight of the dollar bills... also, you don't then have a 50% chance of ending up with only $4. But yes, infinity is very strange. Consider t...

- Thu Jun 21, 2012 8:36 am UTC
- Forum: Mathematics
- Topic: The graph of one to the power x
- Replies:
**10** - Views:
**3159**

### Re: The graph of one to the power x

If and only if there is some rational number r such that pi+r*e is rational, then they will share a root. Since, as is indicated above, the question remain unresolved even for the case of r=1, we may indeed have some trouble. On the bright side, I can say with certainty that when r=0, pi+r*e is irra...

- Thu Jun 21, 2012 8:30 am UTC
- Forum: Mathematics
- Topic: Stuck on an easy-looking combinatorial problem
- Replies:
**3** - Views:
**1018**

### Re: Stuck on an easy-looking combinatorial problem

This problem is indeed solvable by induction. Consider the two-element case: {a, b} The only difference here is a-b, which has multiplicity of 1. This is less that or equal to 1 2 . Therefore, your formula is valid at n=2. Now, assume the formula valid for n, and see if this allows proof that it is ...

- Thu Jun 21, 2012 8:12 am UTC
- Forum: Mathematics
- Topic: Simple yet varied functions that generate the same number
- Replies:
**5** - Views:
**1527**

### Re: Simple yet varied functions that generate the same numbe

Let us say that we limit ourselves to plus, minus, times, divide, exponentiation, and roots. That's six possible operators. Including parenthesis merely means that we can arbitrarily apply these operators in any order, so let us include parenthesis. Numbers; let us limit ourselves to using exactly t...

- Wed Jun 20, 2012 8:09 am UTC
- Forum: Mathematics
- Topic: The graph of one to the power x
- Replies:
**10** - Views:
**3159**

### Re: The graph of one to the power x

With the condition that kj-1 cannot be 0, since otherwise dividing by it is a bad idea. This would imply that both k and j are 1 (or both are -1, but that's basically the same), so the first two equations would be, substituting this in: a + c = b b + d = a So, a + c can (and trivially does) share a...

- Tue Jun 19, 2012 7:46 am UTC
- Forum: Mathematics
- Topic: The graph of one to the power x
- Replies:
**10** - Views:
**3159**

### Re: The graph of one to the power x

What I don't know is whether all irrational numbers have the same set of roots or not. Or even how to tell whether two given irrational numbers have the same set of roots. Would 1 pi and 1 e share any roots besides 1? No they do not, and no they do not. That's what I would expect, but can you prove...