## Search found 4 matches

- Sun Sep 20, 2009 7:34 pm UTC
- Forum: Logic Puzzles
- Topic: Infinite Balls and Jugs [solution]
- Replies:
**611** - Views:
**114080**

### Re: Infinite Balls and Jugs

The problem is too poorly defined to be solvable, because the wording doesn't eliminate the "wrong" method of solving it. Deal. I'll agree there. Just as an addendum, assuming that we have an infinite number of balls (for some reason, people are arguing that we run out of balls to put in ...

- Sun Sep 20, 2009 8:58 am UTC
- Forum: Logic Puzzles
- Topic: Infinite Balls and Jugs [solution]
- Replies:
**611** - Views:
**114080**

### Re: Infinite Balls and Jugs

See, thats where I have the problem. After the nth iteration, where ball n is removed, ball (n+1) still remains. Define for me the final iteration, at midnight, and I'll tell you what the lowest number on a ball in the jar is. EDIT: Agreeing to classify infinity (an undefined number) as a valid numb...

- Sun Sep 20, 2009 8:15 am UTC
- Forum: Logic Puzzles
- Topic: Infinite Balls and Jugs [solution]
- Replies:
**611** - Views:
**114080**

### Re: Infinite Balls and Jugs

Thank you for summaries portions of your argument, Jesting. It definately helps in thinking of these concepts. Still, I'm feeling stubborn, so I'll foolishly and blindly continue :D One flaw that appears on the surface is that \frac{\infty}{\infty} , like \infty-\infty, is an indeterminate form, tha...

- Sun Sep 20, 2009 1:55 am UTC
- Forum: Logic Puzzles
- Topic: Infinite Balls and Jugs [solution]
- Replies:
**611** - Views:
**114080**

### Re: Infinite Balls and Jugs

I really resent these problems. If we look at the ratio of balls left in to balls taken out, every interaction, we get (10 balls in - the ball out)/(the ball out). For n interactions, this is 9n/n. Obviously, resolving this to n=infinity, we get 9(infinity/infinity), which cancels to 9(1/1), or 9. S...