I came across the following question in my homework: determine the limit for x to 3 of (x/3)

^{1/(x-3)}. The previous questions about limits where either solvable by l'Hôpital or Taylor series, but this one seems quite different. If I rewrite it as a fraction, the dividing by 0 still remains. And for the Taylor series, I have no idea how that should be done. I can write something like a

^{x}in Taylor form, but this seems quite impossible and I don't know how I should continue if I manage to rewrite it. Maybe it is a combination of the two, but I think that I'm going off track if I do that. Another thing I tried was writing it as an exponential function (e

^{ln(x/3)...}), but that wasn't useful either

So I'm stuck, I hope you guys could give me a hint about how to solve this thing, because I don't get it..