When I call the function ljx(T,1,1), then ljx(2,2) I get that the row y

_{3}is dependent and can be written as y

_{3}=-y

_{1}+2y

_{2}+1.

When I call the function ljx(T,2,1), then ljx(T,3,2) I get y

_{1}=2y

_{2}-y

_{3}+1 .

If I solve for y

_{3}I get the same answer as at the first case. But the result y

_{1}=2y

_{2}-y

_{3}+1 doesn't mean that y

_{1}is dependent and y

_{3}independent?

Are the results at both cases equal??