X is a pseudorandom number between 85 and 100. All other letters are variables.
H = ((((2 * L / 5 + 2) * A * P / D) / 50) + 2) * S * W/R * X / 100
H = (((( 2L/5 + 2) AP/D) /50) + 2) SWX/100R
H = ((( 2APL /5D + 2AP/ D) / 50) + 2) SWX/100R
H = (( 2APL /250D + 2AP/ 50D) + 2) SWX/100R
H = ( APL /125D + AP/ 25D + 2) SWX/100R
H = APLSWX/12,500DR + APSWX/ 2500DR + 2SWX/100R
H = APLSWX/12,500DR + APSWX/ 2500DR + SWX/50R
H = ( APL/250D + AP/50D + 1) SWX/50R
H = ( AP/50D( L/5 + 1) + 1) SWX/50R
If I made a mistake somewhere up there, I think that I may just explode. If I did not, then we can move on to the next part. I want to figure out the proportion between each variable and H. Here is a far as I could go:
H ∝ S
H ∝ W
H ∝ X
H ∝ 1/50R
Here is where I run into a problem:
H ∝ AP/50D( L/5 + 1) + 1
Now that there is a constant, I am fairly sure that I need to do calculus here. Unfortunately, I have never done calculus with proportions or with more than 2 variables. My guess is that calculus works for equations and proportions identically; I am not sure what to do in a 5 variable calculus problem. Thanks in advance for any help.
Help with a 9 Variable Equation
Moderators: gmalivuk, Moderators General, Prelates

 Posts: 766
 Joined: Fri Feb 07, 2014 3:15 pm UTC
Re: Help with a 9 Variable Equation
what exactly do you mean by proportion of a variable and H? is it the ratio?
Re: Help with a 9 Variable Equation
I don't think you need calculus for this, unless I'm grossly misunderstanding what you're trying to do here. Would you be differentiating or integrating? Why?
The short answer is that H is not directly proportional to A, P, D, or L. If you have some information about the size of H, you can make some approximationsif H >> 1, then you can ignore the constant, for example. But if H is small compared to 1, then you don't have a proportionality.
Personally, if I were approaching this, I would simplify my life by making some composite variables. Starting from your first line, let a = L/5 + 1, b = AP/(50D), c = SWX/(200R), then we just get:
H = (ab + 1)c
Even better, let d = ab
H = (d + 1)c
So H is proportional to (d+1) and to c.
The short answer is that H is not directly proportional to A, P, D, or L. If you have some information about the size of H, you can make some approximationsif H >> 1, then you can ignore the constant, for example. But if H is small compared to 1, then you don't have a proportionality.
Personally, if I were approaching this, I would simplify my life by making some composite variables. Starting from your first line, let a = L/5 + 1, b = AP/(50D), c = SWX/(200R), then we just get:
H = (ab + 1)c
Even better, let d = ab
H = (d + 1)c
So H is proportional to (d+1) and to c.

 Posts: 766
 Joined: Fri Feb 07, 2014 3:15 pm UTC
Re: Help with a 9 Variable Equation
>) wrote:what exactly do you mean by proportion of a variable and H? is it the ratio?
Iff A/B = C, where C is a constant, then A ∝ B.
LaserGuy wrote:I don't think you need calculus for this, unless I'm grossly misunderstanding what you're trying to do here. Would you be differentiating or integrating? Why?
I thought that you would need calculus because differentiating an equation removes any constants and it is the constants that are messing me up.
The short answer is that H is not directly proportional to A, P, D, or L.
Then there has to be something that identifies the relationship A, P, D, and L have with H. I refuse to believe that me, some random guy on the internet, is the first person in human history to try and remove a constant from a proportion.
LaserGuy wrote:If you have some information about the size of H, you can make some approximationsif H >> 1, then you can ignore the constant, for example.
How big does H have to be before it is considered much greater than 1?
Personally, if I were approaching this, I would simplify my life by making some composite variables.
Yeah, but then you would need to substitute the composite variables back out at the end, so no real problem has been solved.
Maybe I should rephrase my question. If I wanted to maximize H, should I double S or triple A.
Re: Help with a 9 Variable Equation
That's the pokémon damage equation right?
The true answer is, it depends. For high enough L and H, you can pretty much assume H to be proportional to A and P, and inversely proportional to D. In earlier game at lower levels the approximation goes off. What I mean is that at high levels, when pokémon have strong attacks, the proportion L*A*P/(D*50) is much larger than 2 so the +2 part does not have much influence and can be neglected.
The point is that it is not exactly proportional, and no kind of algebraic or calculus manipulation is going to change that fact. You can differentiate, integrate, rewrite all you want, but if it's not proportional, it's not proportional.
The true answer is, it depends. For high enough L and H, you can pretty much assume H to be proportional to A and P, and inversely proportional to D. In earlier game at lower levels the approximation goes off. What I mean is that at high levels, when pokémon have strong attacks, the proportion L*A*P/(D*50) is much larger than 2 so the +2 part does not have much influence and can be neglected.
The point is that it is not exactly proportional, and no kind of algebraic or calculus manipulation is going to change that fact. You can differentiate, integrate, rewrite all you want, but if it's not proportional, it's not proportional.
Re: Help with a 9 Variable Equation
jewish_scientist wrote:Maybe I should rephrase my question. If I wanted to maximize H, should I double S or triple A.
I'll start with my equation H = (d + 1)c, where c is proportional to S, and d is proportional to A. If 0 < d < 1/3, then (3d + 1) < 2. So doubling S is better. If d > 1/3, then 3d+1 > 2, so you're better off tripling A.
[edit]More accurate: doubling S is better for 2/3 < d < 1/3; tripling A is better for d < 2/3 or d > 1/3, and they're the same at 2/3 and 1/3.
 Xenomortis
 Not actually a special flower.
 Posts: 1402
 Joined: Thu Oct 11, 2012 8:47 am UTC
Re: Help with a 9 Variable Equation
jewish_scientist wrote:Maybe I should rephrase my question. If I wanted to maximize H, should I double S or triple A.
XY problem?
Look, if you have a Shuckle (very low Attack) attacking a Steelix (very high Defense) with a physical move, there's less point in using Shell Smash (doubling A)  the A/D term is still going to be really small, meaning the "+2" in that equation is going to be quite significant. So the effect of STAB or typemodifiers matters a lot more (the S term in your equation).
On the other hand, if you have something like a Breloom, with a much better Attack stat (making the +2 far less significant), then the using Sky Uppercut (85 Base Power, but also doubling the S term (supereffective against Steelix)) is going to be very similar to using Seed Bomb (80 base power) after a Swords Dance (doubling A).
Who is online
Users browsing this forum: firechicago and 5 guests