Last piece of help I'll need

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Sea Ferring
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Last piece of help I'll need

Postby Sea Ferring » Tue Dec 23, 2008 6:30 am UTC

http://www.vulomedia.com/images/7857212 ... 0650PM.jpg

Step by step tutorial, I know I need to most likely use the Sine law, oblique and right triangle laws, but how exactly?

Eternal thanking will be awarded to who helps me.

Pictures would help.
Image

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Generic Protoplasm
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Re: Last piece of help I'll need

Postby Generic Protoplasm » Tue Dec 23, 2008 6:49 am UTC

Use the law of sines to find the missing side, and use right triangle trig to solve for the height.
Life is like a rock candy, you never know which attribute you're gonna increase next.

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Sea Ferring
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Re: Last piece of help I'll need

Postby Sea Ferring » Tue Dec 23, 2008 7:41 am UTC

Generic Protoplasm wrote:Use the law of sines to find the missing side, and use right triangle trig to solve for the height.


How would I make the right triangle, please draw,

also b= 269.5744624
and a= 298.285155

Nevermind I hope I got it:

http://www.vulomedia.com/images/3578412 ... 5508AM.jpg

Yes? No, help.
Image

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skeptical scientist
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Re: Last piece of help I'll need

Postby skeptical scientist » Tue Dec 23, 2008 8:38 am UTC

Sea Ferring wrote:
Generic Protoplasm wrote:Use the law of sines to find the missing side, and use right triangle trig to solve for the height.


How would I make the right triangle, please draw,

also b= 269.5744624
and a= 298.285155

Nevermind I hope I got it:

http://www.vulomedia.com/images/3578412 ... 5508AM.jpg

Yes? No, help.

No. You're on the right track, but the line in your diagram with length 258m is not the height of the hot air balloon. (In fact, that line is not vertical.)
I'm looking forward to the day when the SNES emulator on my computer works by emulating the elementary particles in an actual, physical box with Nintendo stamped on the side.

"With math, all things are possible." —Rebecca Watson

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Sea Ferring
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Re: Last piece of help I'll need

Postby Sea Ferring » Tue Dec 23, 2008 6:42 pm UTC

skeptical scientist wrote:
Sea Ferring wrote:
Generic Protoplasm wrote:Use the law of sines to find the missing side, and use right triangle trig to solve for the height.


How would I make the right triangle, please draw,

also b= 269.5744624
and a= 298.285155

Nevermind I hope I got it:

http://www.vulomedia.com/images/3578412 ... 5508AM.jpg

Yes? No, help.

No. You're on the right track, but the line in your diagram with length 258m is not the height of the hot air balloon. (In fact, that line is not vertical.)


Could you please just stop dropping hints and give the answer, it's literally the last question and I;ve stopped caring, or a link to a tutorial on how to do this. Please.
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gorcee
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Re: Last piece of help I'll need

Postby gorcee » Tue Dec 23, 2008 6:47 pm UTC

Sea Ferring wrote:
skeptical scientist wrote:
Sea Ferring wrote:
Generic Protoplasm wrote:Use the law of sines to find the missing side, and use right triangle trig to solve for the height.


How would I make the right triangle, please draw,

also b= 269.5744624
and a= 298.285155

Nevermind I hope I got it:

http://www.vulomedia.com/images/3578412 ... 5508AM.jpg

Yes? No, help.

No. You're on the right track, but the line in your diagram with length 258m is not the height of the hot air balloon. (In fact, that line is not vertical.)


Could you please just stop dropping hints and give the answer, it's literally the last question and I;ve stopped caring, or a link to a tutorial on how to do this. Please.


That's not how this forum works!

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Xanthir
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Re: Last piece of help I'll need

Postby Xanthir » Tue Dec 23, 2008 7:15 pm UTC

Sea Ferring wrote:http://www.vulomedia.com/images/7857212222008110650PM.jpg

Step by step tutorial, I know I need to most likely use the Sine law, oblique and right triangle laws, but how exactly?

Eternal thanking will be awarded to who helps me.

Pictures would help.

My rough method:
Spoiler:
Okay, let's identify some lines. We'll call the height of the balloon X. Draw that in, note that it makes a right angle with the ground. You have that.

So, we've got a single unknown, which means we can hopefully use a single equation to solve for it. Unfortunately, the only information we have is a single angle from each of two triangles, and the length of one side that they share. There's no basic equation that you can use which takes the information you have and produces X. So, we're going to need to introduce another equation, and another variable that both equations will use together.

Note that X intersects with the line between the girls. Call the point it hits the ground D. This splits the segment AC into two segments. We don't know the length of these segments, but we can still label them. Say that the line AD has length Y. This means the line DB has length (285 - Y).

Now we can do something. What equations can you use with an angle and *two* sides of a triangle? Write these down for both triangles.

Now that you've got the equations set up, manipulate one so that Y is isolated, then plug it into the other equation. This gives you a single equation with a single variable, which happens to be the variable you're solving for, so solve it and you're done.
(defun fibs (n &optional (a 1) (b 1)) (take n (unfold '+ a b)))

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z4lis
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Re: Last piece of help I'll need

Postby z4lis » Tue Dec 23, 2008 7:26 pm UTC

Take a look at this. You were on the right track, just left out some right angles or had a slip in calculating some angles. Note where I drew in right angles.

http://img186.imageshack.us/img186/9580/mathdiagramba4.jpg
What they (mathematicians) define as interesting depends on their particular field of study; mathematical anaylsts find pain and extreme confusion interesting, whereas geometers are interested in beauty.


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