Solve for x.
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Solve for x.
(tan(2^(y+1) cos(x)))/(sec(2 x)+1) = sin^2(1/y)&&(log(y)+2 i pi (left floor)(arg(y))/(2 pi)+1/2(right floor))^2/(log(2)+log(5))^2!=x
Re: Solve for x.
Clearly x = 7.
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Re: Solve for x.
Skunk wrote:(tan(2^(y+1) cos(x)))/(sec(2 x)+1) = sin^2(1/y)&&(log(y)+2 i pi (left floor)(arg(y))/(2 pi)+1/2(right floor))^2/(log(2)+log(5))^2!=x
That's what SHE said.
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Re: Solve for x.
Solved. Thank you for that thoughtprovoking, intellectually invigorating mental exercise.
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Re: Solve for x.
C programmer's answer:
X could be just about anything, since the last two terms are "!= x".
X could be just about anything, since the last two terms are "!= x".
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Re: Solve for x.
For nearly any remotely sane interpretation of that pair of equations, there is a solution with x = 0. You're going to need to define the && operator for complex values before I can tell you what y is, though.
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Re: Solve for x.
Skunk wrote:Solve for x.
Haha, no.
This is not a forum where we do your homework for you.
Re: Solve for x.
Before we can solve this (which I suspect that no one can, and you just made this up to see how we would react), we have to know what the && means and where the ! is supposed to go.
Re: Solve for x.
Yes, if the purpose of this problem were to determine a value of x such that the equation is a true statement (if such an x exists), then clearly one should use a numerical approach. Just use a root finding algorithm.
If the purpose were to discover some novel problem solving technique in the course of the solution, then it should be stated to solve the problem analyticallybecause most people will refuse to go through the task if there is no interesting feature about it. The problem looks like a waste of time to me.
If the purpose were to discover some novel problem solving technique in the course of the solution, then it should be stated to solve the problem analyticallybecause most people will refuse to go through the task if there is no interesting feature about it. The problem looks like a waste of time to me.
Re: Solve for x.
42?
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Re: Solve for x.
Did that really deserve a thread necro?
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Re: Solve for x.
No.
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