Ok, so I need to find the area of a triangle with the points A=(-2,1) , B=(4,1) , C=(7,4). Having no clear idea how to do this (I feel like I may have learned this somewhere, then forgotten it.) here is what I did.
1- Line segments.
AC= square root of 90 --> Base of Triangle
BC= square root of 18
2- determine height
determine slope of base line segment to be 1/3 , create parallel line running through B, find y-intercept of Line Segment AC and new line running through B, determine distance between the two lines, which gives me a height of 2.
So going into 3, I have base = square root of 90 and height = 2
3- A=(1/2)(b)(h) w/ A=(1/2)(square root of 90)(2) = square root of 90 - reduce to 3(square root of 10).
So, with that as my answer I have to know, is there an easier way to do this that I just forgot? Thanks!