Repeating decimals are x/99...9

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Repeating decimals are x/99...9

Postby Apoapsis » Fri Apr 27, 2012 11:42 pm UTC

Today was a review day in my math class, which translates to: Ask questions entirely unrelated to the subject. :wink:

Anyway, I stumped the teacher today.

An integer i with n digits can be written as:
d_1d_2d_3...d_n

A repeating decimal with i repeating itself (0.iii...) can be written as
\frac {i}{999...9}
with n nines in the denominator.

The question is simple. Why is that?

Thanks!
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Re: Repeating decimals are x/99...9

Postby OverBored » Fri Apr 27, 2012 11:48 pm UTC

Suppose x = 0.{d_1}{d_2}...{d_n}...

Then :

x*(10^n) - x ={d_1}{d_2}...{d_n}.{d_1}{d_2}...{d_n}... - {d_1}{d_2}...{d_n} = {d_1}{d_2}...{d_n}

so x = \frac{{d_1}{d_2}...{d_n}}{{10^n} - 1} = \frac{{d_1}{d_2}...{d_n}}{99.....99}
G4!!

Grob FTW,

Hello. Smithers. You're. Quite good. At. Turning. Me. On.
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