tradiuz wrote:
I tend to look at A_{SK} and think... yes, of course you should ask, that's always the best way to find a possible mate.
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tradiuz wrote:
All My Mushrooms wrote:I'm practicing abstinence until someone offers me sex.
pinkgothic wrote:tradiuz wrote:
I tend to look at A_{SK} and think... yes, of course you should ask, that's always the best way to find a possible mate.
natturner wrote:anyone notice that there should actually be a negative in the exponential of the fourier transform?
pollywog wrote:I want to learn this smile, perfect it, and then go around smiling at lesbians and freaking them out.Wikihow wrote:* Smile a lot! Give a gay girl a knowing "Hey, I'm a lesbian too!" smile.
ConMan wrote:natturner wrote:anyone notice that there should actually be a negative in the exponential of the fourier transform?
There are several equivalent formations of the Fourier transform, each with a corresponding inverse transform. Some move negative signs around, some use a 1/sqrt(2*pi) term in both while others use a single 1/(2*pi), and so forth. They all have different "nice" properties depending on the application.
joedaka wrote:Hey all,
here comes a complete and well structured solution by my friend and me. As it's a quite mathematical answer - and we felt forced to make it a nice LaTeX-made paper.
Have fun reading it
ejleon wrote:Could you possibly post the LaTeX source?
tradiuz wrote:Here is an article that might propose the equation for finding a mate. It's not the equation for love, but it is a good step in the right direction.
xyko wrote:Kinda... nope. [imath]cos \left( Love \right) = sin \left( Love - \frac{\pi}{2} \right)[/imath].
sirKris wrote:What about using a cardoid function, a set of parametric functions, or an implicit curve to represent the heart?
chiggs wrote:We start by noting that hollywood would teach us that love is the only true constant in the Universe (hey - a thousand heroes can' be wrong!). Using this we get immediately:
d/dx (love) = 0, and
[ [ 1 0 ] [ 0 1 ] ](love) = [ [ love 0 ] [ 0 love ] ]
Next, my mother always told me that "friendship is the root of love" and who am I to argue with my mother? So, although I can't pretend to understand how she derived it, I do know that:
sqrt(love) = friendship
For cos(love) I think we have to start with that old "sine" of love "it's in his kiss" as expounded by Cher. Next we note that to us men, women seem to go off on a tangent at random, while I'm sure women think the same of us. Using
cos(love) = sin(love)/tan(love) we get
cos(love) = kiss/women if you're a man and,
cos(love) = kiss/men if you're a woman
Which leaves is with the Fourier transform of a function f(t) into the love domain (which I won't try to write mathematically here). Clearly we can't really answer this unless given a particular function to transform, but whatever the answer is, being "transformed into the love domain" sounds like it must be good.
Colin.
PolakoVoador wrote:Pizza is never a question, pizza is always the answer.
poxic wrote:When we're stuck, flailing, and afraid, that's usually when we're running into the limitations of our old ways of doing things. Something new is being born. Stick around and find out what it is.
Copper Bezel wrote:It's really sweet that you think love is a constant, but I also kinda feel bad.
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